e) 12⋅(11/12-9/10)⋅(3-1 1/3)

e) Выполним действия по порядку.

1. $$1\frac{1}{3} = \frac{1 \cdot 3 + 1}{3} = \frac{3+1}{3} = \frac{4}{3}$$
2. $$3 - \frac{4}{3} = \frac{3 \cdot 3}{1 \cdot 3} - \frac{4}{3} = \frac{9}{3} - \frac{4}{3} = \frac{9-4}{3} = \frac{5}{3}$$
3. $$\frac{11}{12} - \frac{9}{10} = \frac{11 \cdot 5}{12 \cdot 5} - \frac{9 \cdot 6}{10 \cdot 6} = \frac{55}{60} - \frac{54}{60} = \frac{55-54}{60} = \frac{1}{60}$$
4. $$12 \cdot \frac{1}{60} = \frac{12 \cdot 1}{60} = \frac{1}{5}$$
5. $$\frac{1}{5} \cdot \frac{5}{3} = \frac{1 \cdot 5}{5 \cdot 3} = \frac{1 \cdot 1}{1 \cdot 3} = \frac{1}{3}$$

Ответ: $$\frac{1}{3}$$