д) 3/4 k - 12,5 = 9/8 k - 1/8; e) 4,7 - 8z = 4,9 - 10z; ж) 7,3a = 1,6a; з) -19t = 11t.

Решение:

д) \[ \frac{3}{4}k - 12,5 = \frac{9}{8}k - \frac{1}{8} \]

\[ \frac{3}{4}k - \frac{9}{8}k = 12,5 - \frac{1}{8} \]

\[ \frac{6-9}{8}k = \frac{12,5*8 - 1}{8} \]

\[ -\frac{3}{8}k = \frac{100 - 1}{8} \]

\[ -\frac{3}{8}k = \frac{99}{8} \]

\[ k = \frac{99}{8} : (-\frac{3}{8}) \]

\[ k = \frac{99}{8} * (-\frac{8}{3}) \]

k = -33

e) 4,7 - 8z = 4,9 - 10z

-8z + 10z = 4,9 - 4,7

2z = 0,2

z = 0,2/2

z = 0,1

ж) 7,3a = 1,6a

7,3a - 1,6a = 0

5,7a = 0

a = 0

з) -19t = 11t

-19t - 11t = 0

-30t = 0

t = 0