Вопрос:

д) (-pq)⁶. (6p²q)³;

Ответ:

д) (−pq)⁶ ⋅ (6p²q)³ = (−1)⁶ ⋅ p⁶ ⋅ q⁶ ⋅ 6³ ⋅ (p²)³ ⋅ q³ = 1 ⋅ p⁶ ⋅ q⁶ ⋅ 216 ⋅ p⁶ ⋅ q³ = 216 ⋅ (p⁶ ⋅ p⁶) ⋅ (q⁶ ⋅ q³) = 216p¹²q⁹

Ответ: 216p¹²q⁹

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