д) (−pq)⁶ ⋅ (6p²q)³ = (−1)⁶ ⋅ p⁶ ⋅ q⁶ ⋅ 6³ ⋅ (p²)³ ⋅ q³ = 1 ⋅ p⁶ ⋅ q⁶ ⋅ 216 ⋅ p⁶ ⋅ q³ = 216 ⋅ (p⁶ ⋅ p⁶) ⋅ (q⁶ ⋅ q³) = 216p¹²q⁹
Ответ: 216p¹²q⁹