г) (−0,5c⁴d)³ ⋅ (−4c²d²)² = (−0,5)³ ⋅ (c⁴)³ ⋅ d³ ⋅ (−4)² ⋅ (c²)² ⋅ (d²)² = −0,125c¹²d³ ⋅ 16c⁴d⁴ = (−0,125 ⋅ 16) ⋅ (c¹² ⋅ c⁴) ⋅ (d³ ⋅ d⁴) = −2c¹⁶d⁷
Ответ: -2c¹⁶d⁷