Домашнее задание. Четверг. Вычислите:

a) \( \frac{5}{12} + \frac{3}{4} \)

\( \frac{5}{12} + \frac{9}{12} = \frac{14}{12} = \frac{7}{6} \)

б) \( 3 \frac{11}{20} + 2 \frac{19}{30} \)

\( 3 \frac{33}{60} + 2 \frac{38}{60} = 5 \frac{71}{60} = 6 \frac{11}{60} \)

в) \( 9 \frac{5}{6} - 2 \frac{3}{4} \)

\( 9 \frac{10}{12} - 2 \frac{9}{12} = 7 \frac{1}{12} \)

\( (-15,64 : 4 + 7,1) \cdot 2 \frac{2}{5} \)

\( (-3,91 + 7,1) \cdot 2,4 = 3,19 \cdot 2,4 = 7,656 \)

\( (0,4 - \frac{11}{15}) : 1 \frac{2}{7} - (\frac{3}{18} - 0,5) : 1 \frac{1}{6} \)

\( (\frac{2}{5} - \frac{11}{15}) : \frac{9}{7} - (\frac{1}{6} - \frac{1}{2}) : \frac{7}{6} = (\frac{6}{15} - \frac{11}{15}) : \frac{9}{7} - (\frac{1}{6} - \frac{3}{6}) : \frac{7}{6} = -\frac{5}{15} : \frac{9}{7} - (-\frac{2}{6}) : \frac{7}{6} = -\frac{1}{3} \cdot \frac{7}{9} + \frac{1}{3} \cdot \frac{6}{7} = -\frac{7}{27} + \frac{2}{7} = \frac{-49 + 54}{189} = \frac{5}{189} \)

\( 1 - \frac{5}{8} \)

\( \frac{3}{8} \)

\( 1 - \frac{1}{6} \)

\( \frac{5}{6} \)

\( 6 - \frac{2}{5} \)

\( \frac{28}{5} \)