a + 0 = a
a - 0 = a
a + b = b + a
0 + a = a
a - a = 0
(a + b) + c = a + (b + c)
$$(3\frac{2}{5} - 3\frac{2}{5}) + (1\frac{3}{4} - 0) = 0 + 1\frac{3}{4} = 1\frac{3}{4}$$
$$(1\frac{6}{17} + 2\frac{4}{5}) + 5\frac{11}{17} = (1\frac{6}{17} + 5\frac{11}{17}) + 2\frac{4}{5} = (1 + 5 + \frac{6}{17} + \frac{11}{17}) + 2\frac{4}{5} = (6 + \frac{17}{17}) + 2\frac{4}{5} = 7 + 2\frac{4}{5} = 9\frac{4}{5}$$