e) $$3\frac{5}{14} \cdot 7 = \frac{3 \cdot 14 + 5}{14} \cdot 7 = \frac{42+5}{14} \cdot 7 = \frac{47}{14} \cdot 7 = \frac{47 \cdot 7}{14} = \frac{47 \cdot \cancel{7}}{2 \cancel{14}} = \frac{47}{2} = 23\frac{1}{2}$$
Ответ: $$23\frac{1}{2}$$