Evaluate the following expressions: \(\frac{4a^2-1}{a-1} + \frac{1-2a^2}{a-1}\) \(\frac{3x-4y}{x+y} - \frac{2x-y}{x+y}\) \(\frac{a^2-2ab}{a-2b} + \frac{ab-a^2}{a-2b}\) \(\frac{2c-d}{c+2d} - \frac{c-d}{c+2d}\)

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ФИО:Телефон:Емаил:Полное описание сути нарушения прав (почему распространение данной информации запрещено Правообладателем):

Accepted Answer

\(\frac{4a^2-1}{a-1} + \frac{1-2a^2}{a-1} = \frac{4a^2-1+1-2a^2}{a-1} = \frac{2a^2}{a-1}\)
\(\frac{3x-4y}{x+y} - \frac{2x-y}{x+y} = \frac{3x-4y-(2x-y)}{x+y} = \frac{3x-4y-2x+y}{x+y} = \frac{x-3y}{x+y}\)
\(\frac{a^2-2ab}{a-2b} + \frac{ab-a^2}{a-2b} = \frac{a^2-2ab+ab-a^2}{a-2b} = \frac{-ab}{a-2b}\)
\(\frac{2c-d}{c+2d} - \frac{c-d}{c+2d} = \frac{2c-d-(c-d)}{c+2d} = \frac{2c-d-c+d}{c+2d} = \frac{c}{c+2d}\)

Ответ: \(\frac{2a^2}{a-1}\); \(\frac{x-3y}{x+y}\); \(\frac{-ab}{a-2b}\); \(\frac{c}{c+2d}\).