Simplify the expression: \(\frac{2c-3d}{4c} + \frac{c-5d}{4c} - \frac{3c+4d}{4c}\) \(\frac{2p^2+3}{p-1} + \frac{p^2-4}{p-1} - \frac{3p^2-4}{p-1}\)

Решение:

1. \(\frac{2c-3d}{4c} + \frac{c-5d}{4c} - \frac{3c+4d}{4c} = \frac{2c-3d+c-5d-(3c+4d)}{4c} = \frac{3c-8d-3c-4d}{4c} = \frac{-12d}{4c} = \frac{-3d}{c}\)
2. \(\frac{2p^2+3}{p-1} + \frac{p^2-4}{p-1} - \frac{3p^2-4}{p-1} = \frac{2p^2+3+p^2-4-(3p^2-4)}{p-1} = \frac{3p^2-1-3p^2+4}{p-1} = \frac{3}{p-1}\)

Ответ: \(\frac{-3d}{c}\); \(\frac{3}{p-1}\).