Let's analyze the bottom left triangle. Let's denote the vertices as A, B, and C, and point E lies on side BC. Angle A is 90 degrees, angle B is 30 degrees, angle BEC is 60 degrees, and the length of EC is 7. We need to find the length of BE.
First, let's find the angle EAB:
$$\angle EAB = 90 - 60 = 30^{\circ}$$
Now, let's find the angle AEB:
$$\angle AEB = 180 - 60 = 120^{\circ}$$
In triangle BEC, angle ECB $$= 90 - 60 = 30^{\circ}$$. Now let BE be x. Then $$BE = BC - EC$$
Then using tangent we can write:
$$\tan(30) = \frac{AC}{BC}$$
$$\tan(60) = \frac{AC}{EC} = \frac{AC}{7}$$
Therefore
$$AC = 7\tan(60)$$
$$AC = 7\sqrt{3}$$
Now we use the other equation:
$$\tan(30) = \frac{7\sqrt{3}}{BC}$$
$$BC = \frac{7\sqrt{3}}{\tan(30)} = \frac{7\sqrt{3}}{1/\sqrt{3}} = 7\sqrt{3}\sqrt{3} = 21$$
$$BE = BC - EC = 21 - 7 = 14$$
Answer: 14