$\frac{4}{9}\cdot\frac{10}{27}-\left(\frac{11}{15}\cdot\frac{5}{12}+\frac{5}{6}\right)=$

Question

Вопрос: $Фото задания: $\frac{4}{9}\cdot\frac{10}{27}-\left(\frac{11}{15}\cdot\frac{5}{12}+\frac{5}{6}\right)=$$ Фото задания

Accepted Answer

$\frac{4}{9}\cdot\frac{10}{27}=\frac{40}{243}$.

$\frac{11}{15}\cdot\frac{5}{12}=\frac{11}{36}$, поэтому $\frac{11}{36}+\frac{5}{6}=\frac{11}{36}+\frac{30}{36}=\frac{41}{36}$.

$\frac{40}{243}-\frac{41}{36}=\frac{160}{972}-\frac{1107}{972}=-\frac{947}{972}$.

Ответ: $-\frac{947}{972}$.

\(\frac{4}{9}\cdot\frac{10}{27}-\left(\frac{11}{15}\cdot\frac{5}{12}+\frac{5}{6}\right)=\)