г) \(\frac{2^8 \cdot 8^8}{16^7}\) = \(\frac{2^8 \cdot (2^3)^8}{(2^4)^7}\) = \(\frac{2^8 \cdot 2^{24}}{2^{28}}\) = \(\frac{2^{32}}{2^{28}}\) = \(2^{32-28}\) = \(2^4\) = 16
Ответ: 16