г) $$\frac{2p - q}{p^2 + qp} + \frac{p - 2q}{pq + q^2}$$.

г) $$\frac{2p - q}{p^2 + qp} + \frac{p - 2q}{pq + q^2} = \frac{2p - q}{p(p + q)} + \frac{p - 2q}{q(p + q)} = \frac{q(2p - q) + p(p - 2q)}{pq(p + q)} = \frac{2pq - q^2 + p^2 - 2pq}{pq(p + q)} = \frac{p^2 - q^2}{pq(p + q)} = \frac{(p - q)(p + q)}{pq(p + q)} = \frac{p - q}{pq}$$.

Ответ: $$\frac{p - q}{pq}$$