г) (4+1) - 4 = д) (1 + 5) - 2 = e) 7 - (2+4) =

г) $$(4\frac{56}{789} + 1\frac{5}{6}) - 4\frac{56}{789} = 1\frac{5}{6}$$ д) $$(1\frac{6}{11} + 5\frac{16}{39}) - 2\frac{16}{39} = 1\frac{6}{11} + 3 = 4\frac{6}{11}$$ e) $$7\frac{13}{14} - (2\frac{1}{14} + 4\frac{17}{25}) = 7\frac{13}{14} - 2\frac{1}{14} - 4\frac{17}{25} = 5\frac{12}{14} - 4\frac{17}{25} = 1 - \frac{17}{25} + \frac{12}{14} = \frac{8}{25} + \frac{6}{7} = \frac{56+150}{175} = \frac{206}{175} = 1\frac{31}{175} $$

Ответ: смотри выше.