г) (3 2/5 − 5) · (31/48 + 7/24)

\((3\frac{2}{5}-5)\cdot(\frac{31}{48}+\frac{7}{24})=(\frac{17}{5}-\frac{25}{5})\cdot(\frac{31}{48}+\frac{14}{48})\)

\(=-\frac{8}{5}\cdot\frac{45}{48}=-\frac{3}{2}\)

Ответ: \(-\frac{3}{2}\).