г) 2у2 - 9у + 10 = 0;

$$2y^2 - 9y + 10 = 0$$

a = 2, b = -9, c = 10

$$D = (-9)^2 - 4 \cdot 2 \cdot 10 = 81 - 80 = 1$$

$$y_1 = \frac{-b + \sqrt{D}}{2a} = \frac{9 + \sqrt{1}}{2 \cdot 2} = \frac{9 + 1}{4} = \frac{10}{4} = \frac{5}{2} = 2.5$$

$$y_2 = \frac{-b - \sqrt{D}}{2a} = \frac{9 - \sqrt{1}}{2 \cdot 2} = \frac{9 - 1}{4} = \frac{8}{4} = 2$$

Ответ: $$y_1 = 2.5$$, $$y_2 = 2$$