a) $$\left( \frac{5}{8} + 2 \frac{1}{4} \right) \cdot 4 = \left( \frac{5}{8} + \frac{9}{4} \right) \cdot 4 = \frac{5}{8} \cdot 4 + \frac{9}{4} \cdot 4 = \frac{20}{8} + \frac{36}{4} = \frac{5}{2} + 9 = 2 \frac{1}{2} + 9 = 11 \frac{1}{2}$$
б) $$4 \frac{2}{9} \cdot \frac{3}{11} - 3 \frac{5}{9} \cdot \frac{3}{11} = \frac{3}{11} \left( 4 \frac{2}{9} - 3 \frac{5}{9} \right) = \frac{3}{11} \left( \frac{38}{9} - \frac{32}{9} \right) = \frac{3}{11} \cdot \frac{6}{9} = \frac{3 \cdot 6}{11 \cdot 9} = \frac{18}{99} = \frac{2}{11}$$
в) $$3 \frac{2}{9} \cdot \frac{3}{5} + \frac{6}{5} \cdot \frac{3}{9} = \frac{1}{3} \cdot \frac{3}{5} \left( 3 \frac{2}{3} + 2 \right) = \frac{1}{3} \cdot \frac{3}{5} \cdot \left( \frac{11}{3} + 2 \right) = \frac{1}{3} \left( \frac{11}{3} + \frac{6}{3} \right) = \frac{1}{3} \cdot \frac{17}{3} = \frac{17}{9} = 1 \frac{8}{9}$$
Ответ: a) 11 1/2; б) 2/11; в) 1 8/9