6 K 120° x R 24 T

По теореме косинусов:

$$RT^2 = RK^2 + KT^2 - 2 \cdot RK \cdot KT \cdot \cos{\angle K}$$ $$24^2 = x^2 + x^2 - 2 \cdot x \cdot x \cdot \cos{120^\circ}$$ $$576 = 2x^2 - 2x^2 \cdot (-0.5)$$ $$576 = 2x^2 + x^2$$ $$576 = 3x^2$$ $$x^2 = \frac{576}{3}$$ $$x^2 = 192$$ $$x = \sqrt{192} = \sqrt{64 \cdot 3} = 8\sqrt{3}$$

Ответ: $$8\sqrt{3}$$