22) log₁/₂ ³√2 =

$$log_{\frac{1}{2}} \sqrt[3]{2} = x$$

$$(\frac{1}{2})^x = \sqrt[3]{2}$$

$$(\frac{1}{2})^x = 2^{\frac{1}{3}}$$

$$2^{-x} = 2^{\frac{1}{3}}$$

$$x = -\frac{1}{3}$$

Ответ: -1/3