6) log2(3x - 6) - log2 3 = log2 3;

6) log₂(3x - 6) - log₂ 3 = log₂ 3

Используем свойство логарифмов: log_a b - log_a c = log_a (b/c)

log₂((3x - 6)/3) = log₂ 3

(3x - 6)/3 = 3

3x - 6 = 9

3x = 15

x = 5

Проверка:

log₂(3*5 - 6) - log₂ 3 = log₂ 3

log₂(15 - 6) - log₂ 3 = log₂ 3

log₂(9) - log₂ 3 = log₂ 3

log₂(9/3) = log₂ 3

log₂ 3 = log₂ 3

Ответ: x = 5