Н) \(\left(\frac{5}{18}+\frac{7}{12}+\frac{4}{9}\right)\cdot\left(1-\frac{20}{47}\right)\cdot\left(1\frac{1}{4}-\frac{17}{20}\right)\)

Question

Вопрос:

Accepted Answer

\[\frac{5}{18}+\frac{7}{12}+\frac{4}{9}=\frac{10}{36}+\frac{21}{36}+\frac{16}{36}=\frac{47}{36}.\]

\[1-\frac{20}{47}=\frac{27}{47},\qquad 1\frac{1}{4}-\frac{17}{20}=\frac{5}{4}-\frac{17}{20}=\frac{25}{20}-\frac{17}{20}=\frac{2}{5}.\]

\[\frac{47}{36}\cdot\frac{27}{47}\cdot\frac{2}{5}=\frac{3}{4}\cdot\frac{2}{5}=\frac{3}{10}.\]

Ответ: \(\frac{3}{10}\).