1) $$3\frac{1}{4} = \frac{3 \cdot 4 + 1}{4} = \frac{12+1}{4} = \frac{13}{4}$$
$$5\frac{2}{3} = \frac{5 \cdot 3 + 2}{3} = \frac{15+2}{3} = \frac{17}{3}$$
$$7\frac{5}{8} = \frac{7 \cdot 8 + 5}{8} = \frac{56+5}{8} = \frac{61}{8}$$
$$11\frac{3}{4} = \frac{11 \cdot 4 + 3}{4} = \frac{44+3}{4} = \frac{47}{4}$$
$$29\frac{3}{6} = \frac{29 \cdot 6 + 3}{6} = \frac{174+3}{6} = \frac{177}{6}$$
$$17\frac{5}{9} = \frac{17 \cdot 9 + 5}{9} = \frac{153+5}{9} = \frac{158}{9}$$
$$8\frac{5}{6} = \frac{8 \cdot 6 + 5}{6} = \frac{48+5}{6} = \frac{53}{6}$$
Ответ: $$\frac{13}{4}; \frac{17}{3}; \frac{61}{8}; \frac{47}{4}; \frac{177}{6}; \frac{158}{9}; \frac{53}{6}$$