Найди корень уравнения (y-2)/8=(3y-4)/3.

\[\frac{y - 2}{8} = \frac{3y - 4}{3}\]

\[3 \cdot (y - 2) = 8 \cdot (3y - 4)\]

\[3y - 6 = 24y - 32\]

\[24y - 3y = 32 - 6\]

\[21y = 26\]

\[y = 26\ :21\]

\[y = 1\frac{5}{21}.\]