Ответ:
- \(\left(\frac13+\frac19\right)^2=\left(\frac49\right)^2=\frac{16}{81}\).
- \(\left(\frac13\right)^2+\left(\frac19\right)^2=\frac19+\frac1{81}=\frac9{81}+\frac1{81}=\frac{10}{81}\).
- \(\left(\frac13\right)^2+2\cdot\frac13\cdot\frac19+\left(\frac19\right)^2=\frac9{81}+\frac6{81}+\frac1{81}=\frac{16}{81}\).
Следовательно, \(\text{а} = \text{в} > \text{б}\).
Ответ: а) \(\frac{16}{81}\); б) \(\frac{10}{81}\); в) \(\frac{16}{81}\); а = в > б.
