4.333 Найдите частное: a) \(\frac{6}{11} : (-1\frac{4}{11})\); б) \((-1\frac{2}{9}) : 3\frac{2}{3}\); в) -1 \frac{1}{6} : (-\frac{1}{2}); г) -0,18 : (-2 \frac{2}{5}); д) 0,1 : (-\frac{1}{23}); е) -\frac{3}{7} : 2,4.

а) \(\frac{6}{11} : (-1\frac{4}{11}) = \frac{6}{11} : (-\frac{15}{11}) = \frac{6}{11} \cdot (-\frac{11}{15}) = -\frac{6}{15} = -\frac{2}{5} = -0.4\) б) \((-1\frac{2}{9}) : 3\frac{2}{3} = -\frac{11}{9} : \frac{11}{3} = -\frac{11}{9} \cdot \frac{3}{11} = -\frac{3}{9} = -\frac{1}{3} \approx -0.33\) в) \(-1\frac{1}{6} : (-\frac{1}{2}) = -\frac{7}{6} : (-\frac{1}{2}) = -\frac{7}{6} \cdot (-2) = \frac{14}{6} = \frac{7}{3} = 2\frac{1}{3} \approx 2.33\) г) \(-0,18 : (-2 \frac{2}{5}) = -0,18 : (-\frac{12}{5}) = -\frac{18}{100} : (-\frac{12}{5}) = \frac{18}{100} \cdot \frac{5}{12} = \frac{90}{1200} = \frac{3}{40} = 0.075\) д) \(0,1 : (-\frac{1}{23}) = \frac{1}{10} : (-\frac{1}{23}) = \frac{1}{10} \cdot (-23) = -\frac{23}{10} = -2.3\) е) \(-\frac{3}{7} : 2,4 = -\frac{3}{7} : \frac{24}{10} = -\frac{3}{7} \cdot \frac{10}{24} = -\frac{30}{168} = -\frac{5}{28} \approx -0.18\)