Найдите корень уравнения (x-4)/4=(x+3)/7.

\[\frac{x - 4}{4} = \frac{x + 3}{7}\]

\[7 \cdot (x - 4) = 4 \cdot (x + 3)\]

\[7x - 28 = 4x + 12\]

\[7x - 4x = 12 + 28\]

\[3x = 40\]

\[x = \frac{40}{3} = 13\frac{1}{3}.\]