2 Найдите корень уравнения: a) \(\frac{13}{56} + y = \frac{34}{56}\); б) \(\frac{27}{48} + \frac{15}{48} - a = \frac{17}{48}\); в) \(x - \frac{7}{90} = \frac{39}{90}\); г) \(b + \frac{14}{23} - \frac{3}{23} = \frac{20}{23}\);

Решение:

1. \(\frac{13}{56} + y = \frac{34}{56}\) \(y = \frac{34}{56} - \frac{13}{56}\) \(y = \frac{34-13}{56}\) \(y = \frac{21}{56}\) \(y = \frac{3}{8}\)
2. \(\frac{27}{48} + \frac{15}{48} - a = \frac{17}{48}\) \(\frac{42}{48} - a = \frac{17}{48}\) \(a = \frac{42}{48} - \frac{17}{48}\) \(a = \frac{42-17}{48}\) \(a = \frac{25}{48}\)
3. \(x - \frac{7}{90} = \frac{39}{90}\) \(x = \frac{39}{90} + \frac{7}{90}\) \(x = \frac{39+7}{90}\) \(x = \frac{46}{90}\) \(x = \frac{23}{45}\)
4. \(b + \frac{14}{23} - \frac{3}{23} = \frac{20}{23}\) \(b + \frac{11}{23} = \frac{20}{23}\) \(b = \frac{20}{23} - \frac{11}{23}\) \(b = \frac{20-11}{23}\) \(b = \frac{9}{23}\)

Ответ: a) \(y = \frac{3}{8}\); б) \(a = \frac{25}{48}\); в) \(x = \frac{23}{45}\); г) \(b = \frac{9}{23}\)