Найдите корни уравнения (x^2-16) √(x+2)=0.

\[\left( x^{2} - 16 \right)\sqrt{x + 2} = 0\]

\[x^{2} - 16 = 0\]

\[(x - 4)(x + 4) = 0\]

\[x = 4;\ \ x = - 4.\]

\[\sqrt{x + 2} \geq 0\]

\[x + 2 \geq 0\]

\[x \geq - 2.\]

\[Ответ:x = 4;\ \ x = - 2.\]