Найдите разность: а) \(\frac{5}{6}-\frac{5}{10}\); б) \(\frac{3}{20}-\frac{3}{28}\); в) \(\frac{3}{4}-\frac{1}{14}\); г) \(\frac{7}{15}-\frac{2}{39}\); д) \(\frac{26}{33}-\frac{7}{44}\); е) \(\frac{11}{21}-\frac{3}{14}\).

1. \(\frac{5}{6}-\frac{5}{10}=\frac{5}{6}-\frac{1}{2}=\frac{1}{3}\).
2. \(\frac{3}{20}-\frac{3}{28}=\frac{21}{140}-\frac{15}{140}=\frac{3}{140}\).
3. \(\frac{3}{4}-\frac{1}{14}=\frac{21}{28}-\frac{2}{28}=\frac{19}{28}\).
4. \(\frac{7}{15}-\frac{2}{39}=\frac{91}{195}-\frac{10}{195}=\frac{81}{195}=\frac{27}{65}\).
5. \(\frac{26}{33}-\frac{7}{44}=\frac{104}{132}-\frac{21}{132}=\frac{83}{132}\).
6. \(\frac{11}{21}-\frac{3}{14}=\frac{22}{42}-\frac{9}{42}=\frac{13}{42}\).

Ответ: а) \(\frac{1}{3}\); б) \(\frac{3}{140}\); в) \(\frac{19}{28}\); г) \(\frac{27}{65}\); д) \(\frac{83}{132}\); е) \(\frac{13}{42}\).