Найдите решение неравенства 4/(x-2)≥7/(x-3).

\[\frac{4^{\backslash x - 3}}{x - 2} \geq \frac{7^{\backslash x - 2}}{x - 3}\]

\[\frac{4x - 12 - 7x + 14}{(x - 2)(x - 3)} \geq 0\]

\[\frac{- 3x + 2}{(x - 2)(x - 3)} \geq 0\]

\[x = \frac{2}{3};\ \ x = 2;\ \ x = 3\]

\[Ответ:x \in \left( - \infty;\frac{2}{3} \right\rbrack \cup (2;3).\]