17.14. Найдите значение линейной функции, заданной формулой: a) f(x) = 3x – 2, при значении аргумента, равном −3; -1; 0; 2; 7; б) f(x) = 1 − 7х, при значении аргумента, равном -5; -1;0; 3; 10.

• a) f(x) = 3x - 2:
• x = -3: f(-3) = 3*(-3) - 2 = -9 - 2 = -11
• x = -1: f(-1) = 3*(-1) - 2 = -3 - 2 = -5
• x = 0: f(0) = 3*0 - 2 = -2
• x = 2: f(2) = 3*2 - 2 = 6 - 2 = 4
• x = 7: f(7) = 3*7 - 2 = 21 - 2 = 19
• б) f(x) = 1 - 7x:
• x = -5: f(-5) = 1 - 7*(-5) = 1 + 35 = 36
• x = -1: f(-1) = 1 - 7*(-1) = 1 + 7 = 8
• x = 0: f(0) = 1 - 7*0 = 1
• x = 3: f(3) = 1 - 7*3 = 1 - 21 = -20
• x = 10: f(10) = 1 - 7*10 = 1 - 70 = -69

Ответ: a) f(-3) = -11, f(-1) = -5, f(0) = -2, f(2) = 4, f(7) = 19; б) f(-5) = 36, f(-1) = 8, f(0) = 1, f(3) = -20, f(10) = -69