\(5\frac{1}{6}-\frac{7}{4}(a+2\frac{1}{3})\), если a = 2,5.
\(a = 2,5 = \frac{5}{2}\)
\(2\frac{1}{3} = \frac{7}{3}\)
\(5\frac{1}{6} = \frac{31}{6}\)
Тогда:
\(\frac{31}{6}-\frac{7}{4}(\frac{5}{2}+ \frac{7}{3}) = \frac{31}{6}-\frac{7}{4}(\frac{5 \cdot 3 + 7 \cdot 2}{6}) = \frac{31}{6}-\frac{7}{4}(\frac{15+14}{6}) = \frac{31}{6}-\frac{7}{4} \cdot \frac{29}{6} = \frac{31}{6}-\frac{203}{24} = \frac{31 \cdot 4 - 203}{24} = \frac{124 - 203}{24} = \frac{-79}{24} = -3\frac{7}{24}\)
Сравним полученный результат с числом a:
\(-3\frac{7}{24} < 2,5\)
Ответ: \(-3\frac{7}{24}\); \(-3\frac{7}{24} < 2,5\).