a) \(8-\frac{7}{36}x=3\frac{7}{9}\)
\(8 - \frac{7}{36}x = \frac{3 \cdot 9 + 7}{9} = \frac{27+7}{9} = \frac{34}{9}\)
\(-\frac{7}{36}x = \frac{34}{9} - 8 = \frac{34 - 8 \cdot 9}{9} = \frac{34 - 72}{9} = \frac{-38}{9}\)
\(x = \frac{-38}{9} : (-\frac{7}{36}) = \frac{38}{9} \cdot \frac{36}{7} = \frac{38 \cdot 4}{7} = \frac{152}{7} = 21\frac{5}{7}\)
б) \(6\frac{1}{2}-(x+0,25)+3\frac{1}{12}=7\frac{1}{3}\)
\(6\frac{1}{2} - (x + 0,25) + 3\frac{1}{12} = 7\frac{1}{3}\)
\(6\frac{1}{2} + 3\frac{1}{12} - (x + 0,25) = 7\frac{1}{3}\)
\(6\frac{6}{12} + 3\frac{1}{12} - (x + 0,25) = 7\frac{1}{3}\)
\(9\frac{7}{12} - (x + 0,25) = 7\frac{1}{3}\)
\(x + 0,25 = 9\frac{7}{12} - 7\frac{1}{3} = 9\frac{7}{12} - 7\frac{4}{12} = 2\frac{3}{12} = 2\frac{1}{4}\)
\(x + 0,25 = 2,25\)
\(x = 2,25 - 0,25 = 2\)
Ответ: a) \(21\frac{5}{7}\); б) 2.