Найдите значение выражения (3x³)^4 (a⁴)³ ⋅ (a⁵)^3 (3x⁴) при а = − 1 4 и х = −1,25.

\frac{(3x³)^4}{(a⁴)³} ⋅ \frac{(a⁵)³}{(3x⁴)} = \frac{3^4x^(3*4)}{a^(4*3)} ⋅ \frac{a^(5*3)}{3x⁴} = \frac{81x¹²}{a¹²} ⋅ \frac{a¹⁵}{3x⁴} = \frac{81}{3} ⋅ \frac{x¹²}{x⁴} ⋅ \frac{a¹⁵}{a¹²} = 27x^(12-4)a^(15-12) = 27x⁸a³ Подставим значения переменных: 27x⁸a³ = 27 ⋅ (-1,25)⁸ ⋅ (-1/4)³ = 27 ⋅ 1,25⁸ ⋅ (-1)³ / 4³ = -27 ⋅ 14,5519152284 / 64 = -6,1438417489 Ответ: $$-6,1438417489$$