\[x = 1 \frac{1}{7} = \frac{8}{7}\]
\[14xy - 2y + 7x - 1 = 14 \cdot \frac{8}{7} \cdot (-0.6) - 2 \cdot (-0.6) + 7 \cdot \frac{8}{7} - 1\]
\[= 14 \cdot \frac{8}{7} \cdot (-0.6) + 1.2 + 8 - 1\]
\[= 2 \cdot 8 \cdot (-0.6) + 1.2 + 7\]
\[= -9.6 + 1.2 + 7\]
\[= -9.6 + 8.2\]
\[= -1.4\]
Ответ: -1.4