43. Найдите значение выражения и запишите ответ: 1\frac{2}{3}+1\frac{2}{3} 7\frac{4}{5}+1\frac{1}{3} 2\frac{3}{4}+12\frac{2}{3} 6\frac{3}{10}-1\frac{1}{15} 5\frac{11}{12}-2\frac{3}{8} 11\frac{7}{8}-11\frac{5}{6} 44\frac{1}{4}-\frac{1}{6} 11\frac{3}{14}+2\frac{1}{6} 2\frac{1}{15}-1\frac{5}{21} 5\frac{2}{7}+7\frac{2}{5} 6\frac{1}{2}+3\frac{3}{4} 12\frac{1}{2}+2\frac{1}{3}

Решим примеры:

1. $$1\frac{2}{3}+1\frac{2}{3}=1+1+\frac{2}{3}+\frac{2}{3}=2+\frac{4}{3}=2+1\frac{1}{3}=3\frac{1}{3}$$
2. $$7\frac{4}{5}+1\frac{1}{3}=7+1+\frac{4}{5}+\frac{1}{3}=8+\frac{4 \cdot 3}{5 \cdot 3}+\frac{1 \cdot 5}{3 \cdot 5}=8+\frac{12}{15}+\frac{5}{15}=8+\frac{17}{15}=8+1\frac{2}{15}=9\frac{2}{15}$$
3. $$2\frac{3}{4}+12\frac{2}{3}=2+12+\frac{3}{4}+\frac{2}{3}=14+\frac{3 \cdot 3}{4 \cdot 3}+\frac{2 \cdot 4}{3 \cdot 4}=14+\frac{9}{12}+\frac{8}{12}=14+\frac{17}{12}=14+1\frac{5}{12}=15\frac{5}{12}$$
4. $$6\frac{3}{10}-1\frac{1}{15}=6-1+\frac{3}{10}-\frac{1}{15}=5+\frac{3 \cdot 3}{10 \cdot 3}-\frac{1 \cdot 2}{15 \cdot 2}=5+\frac{9}{30}-\frac{2}{30}=5+\frac{7}{30}=5\frac{7}{30}$$
5. $$5\frac{11}{12}-2\frac{3}{8}=5-2+\frac{11}{12}-\frac{3}{8}=3+\frac{11 \cdot 2}{12 \cdot 2}-\frac{3 \cdot 3}{8 \cdot 3}=3+\frac{22}{24}-\frac{9}{24}=3+\frac{13}{24}=3\frac{13}{24}$$
6. $$11\frac{7}{8}-11\frac{5}{6}=11-11+\frac{7}{8}-\frac{5}{6}=0+\frac{7 \cdot 3}{8 \cdot 3}-\frac{5 \cdot 4}{6 \cdot 4}=\frac{21}{24}-\frac{20}{24}=\frac{1}{24}$$
7. $$44\frac{1}{4}-\frac{1}{6}=44+\frac{1}{4}-\frac{1}{6}=44+\frac{1 \cdot 3}{4 \cdot 3}-\frac{1 \cdot 2}{6 \cdot 2}=44+\frac{3}{12}-\frac{2}{12}=44+\frac{1}{12}=44\frac{1}{12}$$
8. $$11\frac{3}{14}+2\frac{1}{6}=11+2+\frac{3}{14}+\frac{1}{6}=13+\frac{3 \cdot 3}{14 \cdot 3}+\frac{1 \cdot 7}{6 \cdot 7}=13+\frac{9}{42}+\frac{7}{42}=13+\frac{16}{42}=13+\frac{8}{21}=13\frac{8}{21}$$
9. $$2\frac{1}{15}-1\frac{5}{21}=2-1+\frac{1}{15}-\frac{5}{21}=1+\frac{1 \cdot 7}{15 \cdot 7}-\frac{5 \cdot 5}{21 \cdot 5}=1+\frac{7}{105}-\frac{25}{105}=1-\frac{18}{105}=\frac{105}{105}-\frac{18}{105}=\frac{87}{105}=\frac{29}{35}$$
10. $$5\frac{2}{7}+7\frac{2}{5}=5+7+\frac{2}{7}+\frac{2}{5}=12+\frac{2 \cdot 5}{7 \cdot 5}+\frac{2 \cdot 7}{5 \cdot 7}=12+\frac{10}{35}+\frac{14}{35}=12+\frac{24}{35}=12\frac{24}{35}$$
11. $$6\frac{1}{2}+3\frac{3}{4}=6+3+\frac{1}{2}+\frac{3}{4}=9+\frac{1 \cdot 2}{2 \cdot 2}+\frac{3}{4}=9+\frac{2}{4}+\frac{3}{4}=9+\frac{5}{4}=9+1\frac{1}{4}=10\frac{1}{4}$$
12. $$12\frac{1}{2}+2\frac{1}{3}=12+2+\frac{1}{2}+\frac{1}{3}=14+\frac{1 \cdot 3}{2 \cdot 3}+\frac{1 \cdot 2}{3 \cdot 2}=14+\frac{3}{6}+\frac{2}{6}=14+\frac{5}{6}=14\frac{5}{6}$$

Ответ: $$3\frac{1}{3}; 9\frac{2}{15}; 15\frac{5}{12}; 5\frac{7}{30}; 3\frac{13}{24}; \frac{1}{24}; 44\frac{1}{12}; 13\frac{8}{21}; \frac{29}{35}; 12\frac{24}{35}; 10\frac{1}{4}; 14\frac{5}{6}$$