44. Выполните действия: 25\frac{5}{11}+3\frac{6}{7} 14\frac{7}{9}-1\frac{1}{6} 2\frac{9}{20}-(\frac{1}{4}+1\frac{1}{5}) \frac{5}{6}+(6\frac{5}{9}-\frac{1}{4})

1. $$25\frac{5}{11}+3\frac{6}{7}=25+3+\frac{5}{11}+\frac{6}{7}=28+\frac{5 \cdot 7}{11 \cdot 7}+\frac{6 \cdot 11}{7 \cdot 11}=28+\frac{35}{77}+\frac{66}{77}=28+\frac{101}{77}=28+1\frac{24}{77}=29\frac{24}{77}$$
2. $$14\frac{7}{9}-1\frac{1}{6}=14-1+\frac{7}{9}-\frac{1}{6}=13+\frac{7 \cdot 2}{9 \cdot 2}-\frac{1 \cdot 3}{6 \cdot 3}=13+\frac{14}{18}-\frac{3}{18}=13+\frac{11}{18}=13\frac{11}{18}$$
3. $$2\frac{9}{20}-(\frac{1}{4}+1\frac{1}{5})=2\frac{9}{20}-(\frac{1}{4}+1+\frac{1}{5})=2\frac{9}{20}-(1+\frac{1}{4}+\frac{1}{5})=2\frac{9}{20}-(1+\frac{1 \cdot 5}{4 \cdot 5}+\frac{1 \cdot 4}{5 \cdot 4})=2\frac{9}{20}-(1+\frac{5}{20}+\frac{4}{20})=2\frac{9}{20}-(1+\frac{9}{20})=2\frac{9}{20}-1\frac{9}{20}=2-1+\frac{9}{20}-\frac{9}{20}=1+0=1$$
4. $$\frac{5}{6}+(6\frac{5}{9}-\frac{1}{4})=\frac{5}{6}+(6+\frac{5}{9}-\frac{1}{4})=\frac{5}{6}+6+(\frac{5}{9}-\frac{1}{4})=6+\frac{5}{6}+(\frac{5 \cdot 4}{9 \cdot 4}-\frac{1 \cdot 9}{4 \cdot 9})=6+\frac{5}{6}+(\frac{20}{36}-\frac{9}{36})=6+\frac{5}{6}+\frac{11}{36}=6+\frac{5 \cdot 6}{6 \cdot 6}+\frac{11}{36}=6+\frac{30}{36}+\frac{11}{36}=6+\frac{41}{36}=6+1\frac{5}{36}=7\frac{5}{36}$$

Ответ:$$29\frac{24}{77}; 13\frac{11}{18}; 1; 7\frac{5}{36}$$