a) \(\frac{11}{50} - \frac{3}{25} + \frac{1}{20} = \frac{22}{100} - \frac{12}{100} + \frac{5}{100} = \frac{22-12+5}{100} = \frac{15}{100} = \frac{3}{20}\)
в) \(2\frac{1}{8} + 3\frac{5}{12} = 2\frac{3}{24} + 3\frac{10}{24} = 5\frac{13}{24}\)
д) \(7\frac{3}{8} - 3\frac{5}{6} = 7\frac{9}{24} - 3\frac{20}{24} = 6\frac{33}{24} - 3\frac{20}{24} = 3\frac{13}{24}\)
б) \(8 - 3\frac{6}{7} = 7\frac{7}{7} - 3\frac{6}{7} = 4\frac{1}{7}\)
г) \(5\frac{13}{15} + 1\frac{7}{12} = 5\frac{52}{60} + 1\frac{35}{60} = 6\frac{87}{60} = 7\frac{27}{60} = 7\frac{9}{20}\)
Ответ: a) \(\frac{3}{20}\); в) \(5\frac{13}{24}\); д) \(3\frac{13}{24}\); б) \(4\frac{1}{7}\); г) \(7\frac{9}{20}\).