Ответ: 11
б) $$\sin{(-\pi)}-\cos{\frac{3\pi}{2}}+2\sin{2\pi}-\text{tg}{\pi} = 0 - 0 + 2 \cdot 0 - 0 = 0$$Ответ: 0
в) $$3-\sin^2{\frac{\pi}{3}}+2\cos^2{\frac{\pi}{2}}-5\text{tg}^2{\frac{\pi}{4}} = 3 - (\frac{\sqrt{3}}{2})^2 + 2 \cdot 0^2 - 5 \cdot 1^2 = 3 - \frac{3}{4} + 0 - 5 = -2 - \frac{3}{4} = -2\frac{3}{4} = -2.75$$Ответ: $$-2\frac{3}{4} = -2.75$$
г) $$3\sin^2{\frac{\pi}{2}}-4\text{tg}^2{\frac{\pi}{4}}-3\cos^2{\frac{\pi}{6}}+3\text{ctg}^2{\frac{\pi}{2}} = 3 \cdot 1^2 - 4 \cdot 1^2 - 3 \cdot (\frac{\sqrt{3}}{2})^2 + 3 \cdot 0^2 = 3 - 4 - 3 \cdot \frac{3}{4} + 0 = -1 - \frac{9}{4} = -1 - 2\frac{1}{4} = -3\frac{1}{4} = -3.25$$Ответ: $$-3\frac{1}{4} = -3.25$$