Решение:

А)

$$ (-0.2 + \frac{1}{3}) \div (-3.2) = (-\frac{1}{5} + \frac{1}{3}) \div (-\frac{32}{10}) = (\frac{-3 + 5}{15}) \div (-\frac{16}{5}) = \frac{2}{15} \cdot (-\frac{5}{16}) = \frac{2}{3 \cdot 5} \cdot (-\frac{5}{2 \cdot 8}) = -\frac{1}{3 \cdot 8} = -\frac{1}{24} $$ Ответ: $$-\frac{1}{24}$$

Б)

$$ (-0.5 - (-\frac{3}{4})) \div (-0.2) = (-\frac{1}{2} + \frac{3}{4}) \div (-\frac{1}{5}) = (\frac{-2 + 3}{4}) \div (-\frac{1}{5}) = \frac{1}{4} \cdot (-5) = -\frac{5}{4} = -1.25 $$ Ответ: $$-1.25$$

В)

$$ (-0.3 - \frac{1}{5}) \div (-\frac{1}{6}) = (-\frac{3}{10} - \frac{1}{5}) \div (-\frac{1}{6}) = (\frac{-3 - 2}{10}) \div (-\frac{1}{6}) = -\frac{5}{10} \cdot (-6) = -\frac{1}{2} \cdot (-6) = 3 $$ Ответ: $$3$$

Г)

$$ -3\frac{7}{20} + (-0.25 \div (-\frac{1}{4}) - 1.5 \div (-\frac{3}{16})) \div (-4\frac{1}{11}) = -3.35 + (-0.25 \cdot (-4) - 1.5 \cdot (-\frac{16}{3})) \div (-\frac{45}{11}) = -3.35 + (1 + \frac{1.5 \cdot 16}{3}) \div (-\frac{45}{11}) = -3.35 + (1 + \frac{3 \cdot 16}{2 \cdot 3}) \div (-\frac{45}{11}) = -3.35 + (1 + 8) \div (-\frac{45}{11}) = -3.35 + 9 \cdot (-\frac{11}{45}) = -3.35 - \frac{11}{5} = -3.35 - 2.2 = -5.55 $$ Ответ: $$-5.55$$

Д)

$$ (-\frac{1}{3} + \frac{1}{2}) \cdot 0.6 - 0.6 \div (-\frac{3}{5}) = (\frac{-2+3}{6}) \cdot 0.6 - 0.6 \cdot (-\frac{5}{3}) = \frac{1}{6} \cdot \frac{6}{10} + \frac{0.6 \cdot 5}{3} = \frac{1}{10} + \frac{3}{3} = 0.1 + 1 = 1.1 $$ Ответ: $$1.1$$

Е)

$$ (6\frac{8}{25} \div (-1) - (-0.8) \cdot (-0.1)) \div (-0.25 \div 1.25 - 1\frac{3}{5} \div (-5\frac{1}{3})) = (\frac{158}{25} \div (-1) - 0.08) \div (-\frac{1}{4} \div \frac{5}{4} - \frac{8}{5} \div (-\frac{16}{3})) = (-\frac{158}{25} - \frac{2}{25}) \div (-\frac{1}{4} \cdot \frac{4}{5} + \frac{8}{5} \cdot \frac{3}{16}) = -\frac{160}{25} \div (-\frac{1}{5} + \frac{3}{10}) = -\frac{32}{5} \div (\frac{-2+3}{10}) = -\frac{32}{5} \div \frac{1}{10} = -\frac{32}{5} \cdot 10 = -32 \cdot 2 = -64 $$ Ответ: $$-64$$