Решение задания 727

• a) $$sin(-30°) = -sin(30°) = -\frac{1}{2} = -0.5$$


• б) $$cos(-60°) = cos(60°) = \frac{1}{2} = 0.5$$


• в) $$tg(-45°) = -tg(45°) = -1$$


• г) $$ctg(-30°) = -ctg(30°) = -\sqrt{3}$$


• д) $$cos(-90°) = cos(90°) = 0$$


• e) $$sin(-45°) = -sin(45°) = -\frac{\sqrt{2}}{2}$$