Решение:
$$1 \frac{1}{7} \cdot (\frac{1}{3} + \frac{1}{8} + \frac{5}{12}) - \frac{1}{5} + \frac{1}{10} = \frac{8}{7} \cdot (\frac{8}{24} + \frac{3}{24} + \frac{10}{24}) - \frac{1}{5} + \frac{1}{10} = \frac{8}{7} \cdot \frac{21}{24} - \frac{1}{5} + \frac{1}{10} = \frac{8 \cdot 21}{7 \cdot 24} - \frac{1}{5} + \frac{1}{10} = \frac{8 \cdot 3 \cdot 7}{7 \cdot 8 \cdot 3} - \frac{1}{5} + \frac{1}{10} = 1 - \frac{1}{5} + \frac{1}{10} = 1 - \frac{2}{10} + \frac{1}{10} = 1 - \frac{1}{10} = \frac{10}{10} - \frac{1}{10} = \frac{9}{10}$$
Ответ: $$\frac{9}{10}$$