1) A: $$(ab)^2 \cdot (-5a^4b^5)$$$$= a^2b^2 \cdot (-5a^4b^5) = -5a^{2+4}b^{2+5} = -5a^6b^7$$
B: $$-6x^7y \cdot 5x^3y^2 \cdot 2xy^2$$$$= -6 \cdot 5 \cdot 2 \cdot x^{7+3+1}y^{1+2+2} = -60x^{11}y^5$$
Ответ: A: $$-5a^6b^7$$, B: $$-60x^{11}y^5$$