7 - 0,01p7 (-10p2)3 (α6 bc2)3 (αb2c)2

7) A: $$-0.01p^7 \cdot (-10p^2)^3 = -0.01p^7 \cdot (-1000p^6) = 10p^{7+6} = 10p^{13}$$

B: $$(\alpha^6bc^2)^3 \cdot (\alpha b^2c)^2 = \alpha^{18}b^3c^6 \cdot \alpha^2b^4c^2 = \alpha^{18+2}b^{3+4}c^{6+2} = \alpha^{20}b^7c^8$$

Ответ: A: $$10p^{13}$$, B: $$\alpha^{20}b^7c^8$$