Ответ:
Решение:
а) \(\frac{1}{3} + \frac{1}{2} = \frac{1 × 2}{3 × 2} + \frac{1 × 3}{2 × 3} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6}\)
б) \(\frac{2}{5} + \frac{3}{10} = \frac{2 × 2}{5 × 2} + \frac{3}{10} = \frac{4}{10} + \frac{3}{10} = \frac{7}{10}\)
в) \(\frac{7}{12} - \frac{3}{12} = \frac{7 - 3}{12} = \frac{4}{12} = \frac{1}{3}\)
г) \(\frac{11}{12} - \frac{3}{4} = \frac{11}{12} - \frac{3 × 3}{4 × 3} = \frac{11}{12} - \frac{9}{12} = \frac{2}{12} = \frac{1}{6}\)
д) \(\frac{4}{15} + \frac{3}{12}\). Общий знаменатель 60: \(\frac{4 × 4}{15 × 4} + \frac{3 × 5}{12 × 5} = \frac{16}{60} + \frac{15}{60} = \frac{31}{60}\)
е) \(\frac{2}{9} + \frac{1}{3} = \frac{2}{9} + \frac{1 × 3}{3 × 3} = \frac{2}{9} + \frac{3}{9} = \frac{5}{9}\)
Ответ: а) \(\frac{5}{6}\); б) \(\frac{7}{10}\); в) \(\frac{1}{3}\); г) \(\frac{1}{6}\); д) \(\frac{31}{60}\); е) \(\frac{5}{9}\).
