Please provide the balanced chemical equation for the reaction between K₂S and HBr.

Okay, let's balance the chemical equation for the reaction between potassium sulfide (K₂S) and hydrobromic acid (HBr).

The unbalanced equation is:

$$K_2S + HBr \rightarrow KBr + H_2S$$

Now, let's balance it step by step:

1. Balance Potassium (K): There are 2 potassium atoms on the left side (K₂S), so we need 2 potassium atoms on the right side. We add a coefficient of 2 in front of KBr:

   $$K_2S + HBr \rightarrow 2KBr + H_2S$$

2. Balance Bromine (Br): Now we have 2 bromine atoms on the right side (2KBr), so we need 2 bromine atoms on the left side. We add a coefficient of 2 in front of HBr:

   $$K_2S + 2HBr \rightarrow 2KBr + H_2S$$

3. Balance Hydrogen (H): We now have 2 hydrogen atoms on the left side (2HBr), and 2 hydrogen atoms on the right side (H₂S), so hydrogen is already balanced.

4. Balance Sulfur (S): We have 1 sulfur atom on the left side (K₂S) and 1 sulfur atom on the right side (H₂S), so sulfur is balanced.

The balanced chemical equation is:

$$K_2S + 2HBr \rightarrow 2KBr + H_2S$$

Answer: The balanced chemical equation is $$K_2S + 2HBr \rightarrow 2KBr + H_2S$$.