Постройте график функции: f(x)=3-x; x^2-2x+1; 4.

Question

\[f(x) = 3 - x\]

\[x\]	\[0\]	\[1\]
\[y\]	\[3\]	\[2\]

\[f(x) = x^{2} - 2x + 1\]

\[x_{0} = 1,\ \ y_{0} = 0\]

Accepted Answer

\[f(x) = 3 - x\]

\[x\]	\[0\]	\[1\]
\[y\]	\[3\]	\[2\]

\[f(x) = x^{2} - 2x + 1\]

\[x_{0} = 1,\ \ y_{0} = 0\]

Ответ: