Ответ:
\[y = - \frac{2}{x + 1};\ \ \ \ \ \ \ x + 1 \neq 0;\ \ \ \ \]
\[x \neq - 1\]
| \[x\] | \[0\] | \[1\] | \[3\] | \[- 2\] | \[- 3\] | \[- 5\] |
|---|---|---|---|---|---|---|
| \[y\] | \[- 2\] | \[- 1\] | \[- 0,5\] | \[2\] | \[1\] | \[0,5\] |
\[D(y) = ( - \infty; - 1) \cup ( - 1; + \infty).\]

\[y = - \frac{2}{x + 1};\ \ \ \ \ \ \ x + 1 \neq 0;\ \ \ \ \]
\[x \neq - 1\]
| \[x\] | \[0\] | \[1\] | \[3\] | \[- 2\] | \[- 3\] | \[- 5\] |
|---|---|---|---|---|---|---|
| \[y\] | \[- 2\] | \[- 1\] | \[- 0,5\] | \[2\] | \[1\] | \[0,5\] |
\[D(y) = ( - \infty; - 1) \cup ( - 1; + \infty).\]
