Ответ:
\[y = x^{2} - 2x\]
| \[x\] | \[0\] | \[1\] | \[2\] | \[- 1\] | \[3\] |
|---|---|---|---|---|---|
| \[y\] | \[0\] | \[- 1\] | \[0\] | \[3\] | \[3\] |

\[y \nearrow \ \ \ при\ \ x \in \lbrack 1; + \infty)\]
\[y \searrow при\ x \in ( - \infty;1\rbrack\]
\[y = x^{2} - 2x\]
| \[x\] | \[0\] | \[1\] | \[2\] | \[- 1\] | \[3\] |
|---|---|---|---|---|---|
| \[y\] | \[0\] | \[- 1\] | \[0\] | \[3\] | \[3\] |

\[y \nearrow \ \ \ при\ \ x \in \lbrack 1; + \infty)\]
\[y \searrow при\ x \in ( - \infty;1\rbrack\]