Преобразуйте в дробь выражение: a) $$x + \frac{1}{y}$$; б) $$1 - a$$ в) $$3a - \frac{a}{4}$$; г) $$5b - \frac{2}{b}$$; д) $$\frac{a^2 + b}{a} - a$$ e) $$2p - \frac{4p^2 + 1}{2p}$$; ж) $$\frac{(a-b)^2}{2a} + b$$ з) $$c - \frac{(b+c)^2}{2b}$$

а) $$x + \frac{1}{y} = \frac{xy + 1}{y}$$

б) $$1 - a = \frac{1}{a} - a = \frac{1 - a^2}{a}$$

в) $$3a - \frac{a}{4} = \frac{12a - a}{4} = \frac{11a}{4}$$

г) $$5b - \frac{2}{b} = \frac{5b^2 - 2}{b}$$

д) $$\frac{a^2 + b}{a} - a = \frac{a^2 + b - a^2}{a} = \frac{b}{a}$$

е) $$2p - \frac{4p^2 + 1}{2p} = \frac{4p^2 - 4p^2 - 1}{2p} = -\frac{1}{2p}$$

ж) $$\frac{(a-b)^2}{2a} + b = \frac{a^2 - 2ab + b^2 + 2ab}{2a} = \frac{a^2 + b^2}{2a}$$

з) $$c - \frac{(b+c)^2}{2b} = \frac{2bc - (b^2 + 2bc + c^2)}{2b} = \frac{2bc - b^2 - 2bc - c^2}{2b} = \frac{-b^2 - c^2}{2b} = -\frac{b^2 + c^2}{2b}$$